NZBGet : Search

see comment on your post here: https://www.reddit.com/r/usenet/comment ... &context=3

45.0 GB, 0:03:35 Unpack time 47.2 GB, 0:08:50 Unpack time 50.8 GB, 0:31:32 Unpack time 15.5 GB, 0:00:15 Unpack time 49.0 GB, 0:54:35 Unpack time 15.5 GB, 0:00:15 Unpack time ... so 15 GB in 15 seconds, or 1GB/s = 1000 MB/s ... which is very fast. - A M.2 SATA SSD can achieve 500 MB/s or so. - A M.2...

OK, as I don't have the unlimited aka 1PB ... back to you: With this python3 script named show_free_diskspace.py #!/usr/bin/python3 import os, sys mydir = sys.argv[1] st = os.statvfs(mydir) print(st) myfree = st.f_bavail * st.f_frsize print("Free:", myfree) print("Free GB:", int(myfree/(1024*1024*10...

Ouch: my https://drive.google.com/drive/my-drive says "55.8 GB of 101 GB used". Ah, so in my case the "df -h" is showing the correct space.

So ... how do you get the 1PB and 2PB? Is that goolge language for a unlimited plan?

Out of curiosity, I tried out rclone. It works, but after a mount like this rclone mount google-drive:LinuxDocs /home/sander/myGoogleDrive_LinuxDocs (which works; I can copy to that directory) a `df -h` still show the space of my local disk, and not 1PB or so google-drive:LinuxDocs 101G 7,3G 46G 14%...

They are rclone mounts. Each mount is registered as 1pb, so when 2 are merged it becomes 2pb. Can I change the code somehow to work with the 2.1pb? First things first: find any method to find the real available space ... Preferrably via statvfs() EDIT: Wait ... if rclone space indeed is 2.1PB as re...

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So, df -h tells you /mnt/unionfs has free ... 2.1PB. That is 2100 TB. <insert sound of one million dollars dr evil> 2.1PB is 2,1e+9 MB = 2.100.000.000 MB which is indeed around the 2^32 + -2.146.640.073 which I suggested. But back to your 2.1PB: do you really have 2100 TB diskspace? So 400 disks of ...

2's complement problem? -2146640073 + 2^32 is ... 2147483648. Coincidence? What does df -h /your/dir report about that diskspace? AFAIK the relevant code in nzbget is this: int64 FileSystem::FreeDiskSize(const char* path) { //snip struct statvfs diskdata; if (!statvfs(path, &diskdata)) { return (int...

"FileSizeLo" : -1495418638, "FileSizeHi" : 15, A two's complement problem? What if you add 4.2G to that, would that make sense? You would get 2^32 -1495418638 = 2799548658 FileSizeLo (int) - Initial size of all files in group in bytes, Low 32-bits of 64-bit value. FileSizeHi (int) - Initial size of ...